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Matching the AMT300...
 
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Matching the AMT3000 to 50ohms

 
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Last Post by Anonymous 9 years ago
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 Anonymous
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No need to apologize. We all have a life outside of this hobby, and life tends to get in the way a lot.

Now your talking results with the unmodulated carrier..which is what should be happening with that unit.

Look forward to hearing about the 50 ohm match network results.

RFB


 
Posted : 22/02/2012 6:08 pm
 Anonymous
(@Anonymous)
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The output stage of the AMT 3000 is a differential amplifier. This is a variant of the common emitter (CE) amplifier. The output impedance of a CE amplifier is (for all practical applications) equivalent to the resistor between the collector and the power supply. For the AMT 3000 this is R18 which id 820 ohms. For a differential amp circuit we double that value, so the output impedance is 1640 ohms. With that as a starting point, one could calculate the remainder of the component value so that the output impendance of the AMT 3000 is 50 ohms. The only remaining value to consider is the Q factor of the pi network consisting of C5, C23, and the combination of L4, L5, L6, L7. 

For my case I am using a transmit frequency of 1.7 MHz (1700 KHz). The Q factor of the pi network for an unmodified AMT 3000 is about 50, and the output impedance is about 39K ohms (no antenna connected) yielding a value of 120 pF for C5. If I stick with that Q factor (50) and change the output impedance to 50 ohms then I get a value of 3.6 uH for the combination of L4-L7 and a value of 2854 pF (about 0.003 mF) for C23. The value of C5 would be 16242 pF (0.016 mF).


 
Posted : 01/01/2017 6:32 am
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