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Last Post by Anonymous 9 years ago
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 Anonymous
(@Anonymous)
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So Leonard wherein those calculations did you figure HAAT, and what's your calculation figure on ground reflectivity, and where's the calculation for soil conductivity, you're still squinting at this as if it was grounded in theory so you apply those rules for big boy antennas and believe you're following the letter so it must apply to my part 15 peanut whistles.
Also while we are calculating for my signal being propagated by a 300ft tall 8 wire high-tension electrical tower that runs thru my town behind my home and cuts across the state bringing thousands of wind turbines wires behind me thousands of volts thru those lovely propagators  ...You see you are looking at this thru a keyhole and stating what only you see as it should look to you not even what's being seen. take a closer look your on the great lakes come on over my guest you could pick up that $500. bounty I have for anyone who can find anything in fcc violation with my transmitter install ... Come one come all.. when your in town give me a ring.. i will have the coffee on and some fresh coffee cake waiting for ya sir 🙂


 
Posted : 02/06/2017 3:15 am
 Anonymous
(@Anonymous)
Posts: 0
 

In free space, all electromagnetic waves (radio, light, X-rays, etc.) obey the inverse-square law which states that the power density {displaystyle rho ,} rho , of an electromagnetic wave is proportional to the inverse of the square of the distance {displaystyle r,} r, from a point source[3] or:

{displaystyle rho propto {frac {1}{r^{2}}}.} {displaystyle rho propto {frac {1}{r^{2}}}.}
At typical communication distances from a transmitter, the transmitting antenna usually can be approximated by a point source. Doubling the distance of a receiver from a transmitter means that the power density of the radiated wave at that new location is reduced to one-quarter of its previous value.

The power density per surface unit is proportional to the product of the electric and magnetic field strengths. Thus, doubling the propagation path distance from the transmitter reduces each of these received field strengths over a free-space path by one-half. Thus this inverse ratio of double the power at the receiver gained by the efficiency of the surrounding areas highly efficient propagators being my preferred amplification method using HAAT as my sole means of propagating out to the high tension wires behind me that carry my signals for miles and miles and miles and miles. Would you like me to remove those 300ft towers so your calculations could come into line with what you believe is the only factor in my amazing performance? 

I really wish someone would stop by so we could figure out this situation 

 

🙂


 
Posted : 02/06/2017 3:50 am
 Anonymous
(@Anonymous)
Posts: 0
 

You cannot keep Pai out of your posts? You're morphing into Rich Fry. Do you have any Pai Charts you could share?


 
Posted : 02/06/2017 4:57 am
 Anonymous
(@Anonymous)
Posts: 0
 


 
Posted : 02/06/2017 5:00 am
 Anonymous
(@Anonymous)
Posts: 0
 

This thread is not accomplishing anything, and is now locked.


 
Posted : 02/06/2017 6:30 am
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